Open File Dialog help in visual basic 2005?

i am using an open file dialog in visual basic to open the file ,the user has to click open twice to open the file(in the first click the dialog refreshes with the selected filename) what should i do i want the user to click only once to open the file.Heres the code i used





OpenFileDialog1.FileName = ""





OpenFileDialog1.ShowDialog()





If OpenFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then


Dim c As String = Me.OpenFileDialog1.FileName


Dim cc As String = IO.File.ReadAllText(c)


Me.RichTextBox1.Text = cc


Else





End If

Open File Dialog help in visual basic 2005?
Try


With OpenFileDialog1


.Filter = "Text files (*.txt)|*.txt|" %26amp; "All files|*.*"


If .ShowDialog() = DialogResult.OK Then


FileName = .FileName


sr = New StreamReader(.OpenFile)


RichTextBox1.Text = sr.ReadToEnd()


End If


End With


Catch es As Exception


MessageBox.Show(es.Message)


Finally


If Not (sr Is Nothing) Then


sr.Close()


End If


End Try








the above code is to read the given txt file from open dialog box and then showing the text file content in the richtext box..





the above code is in vs2003 .. the similar way only u can do it in vs 2005 not much different ..





hope u got ur answer...





keep askin question





regards


rajan

poppy